(x-3)^2=4(x+5)

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Solution for (x-3)^2=4(x+5) equation: 



(x-3)^2=4(x+5)

We move all terms to the left:

(x-3)^2-(4(x+5))=0



We calculate terms in parentheses: -(4(x+5)), so:

4(x+5)

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

(x-3)^2-4x-20=0

We add all the numbers together, and all the variables

-4x+(x-3)^2-20=0

We move all terms containing x to the left, all other terms to the right

-4x+(x-3)^2=20

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